[her_name_here_]: the guide to formal denouement after a guy gets blocked by a once friend and now deserter
:in medias res, But only minusculely. Check it .0048 is what your chances are if I took away 5% of your luck and with that I will tell you I actually lied because us knowing one another is actually in the 1998th percentile when there's 1000 [her_name_here_] because there's 2000 possible pairs between me and a [her_name_here_] so relationships are 50/50 but that's not good enough I will bolster chances by 50 because that is another [her_name_here_] in a pair so 50 x .0048 even with 5 percent less luck you have 1200. 1200/1998 - 1(1002/1002) for possible [her_name_here_] and me total participants and you get less than 200/998 because I subtracted more than 1(1.001999999) even though you know thats not the correct conversion of denominator LCD and with the 200/998 you can extrapolate 2 in a pair one pair for every 9.98 [her_name_here_] if there were 1000 but I cannot clone myself 199 times and furthermore with the previous expression you get .198396793587 which is not only less than .22 et cetera that you get with 200/998 but also less than a single pair per 1002 including me participants and I was kind enough to give you 1000 [her_name_here_] because any more would be subtracting more than 1003/1003 or bolstered more than 1.002/1.000 to account for all of us. Also, I only accounted for one 7 digit line, and simply put, if I added even 3 guaranteed numbers of another [her_name_here_] phone that's 70/30 relationship which is what I get if you physically tried to raise your chances by moving to New York to match me and to bolster you get 70/30 + 1/7 - ((9/6 x 1/10)-(9/10)) which gets you only 1.7261904761904 not a pair ;( now humans having phone numbers give you a better chance but not quite a pair to refute the 1998th percentile. And don't try to change the equation to accompany [her_name_here_]participants or even phone numbers because I don't have any of theirs besides yours! P.S. November 2021 blockdate intro, completion, and bygone storage: in bolstering stats I found there's only one [her_name_here_] who can recall who this is so that means you're in the 999th percentile of all the [her_name_here_] that I could ever be friends with unless you know at least 1000+ [her_name_here_] exist in the world 1001+ including you would prove me wrong but that doesn't mean I know those 6 different numbers in a certain order that constitutes a cell phone number compounded by those over 1000 Vikas that can possibly or probably prove me wrong about the 999th percentile or the fact that we're friends: there's a 6 x 1/1000 + 1/(1000/1000) chance which is actually 1006 over 1000 so basically less than a .006 chance that there's another Devika besides you that I know and less than .006 if, and you have no control over this, there exists at least 1002 Vickys to ever exist in the world including if they died before 6 digit phone numbers it takes to be different from your 7 digit number. Bc .006 x 999 gives you more than 1 [her_name_here_].
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